如何一行代码实现将两个数组交叉

@013231 我的机子上的结果.

In [18]: timeit list(itertools.chain(*zip(t,m)))
1000000 loops, best of 3: 773 ns per loop

In [19]: timeit reduce(lambda x, y: x + y, zip(t, m))
1000000 loops, best of 3: 549 ns per loop

@9hills 確實如此.

In [719]: a = range(100000)

In [720]: b = range(100000)

In [721]: cProfile.run('reduce(lambda x, y: x + y, zip(a, b))')
100003 function calls in 46.933 seconds

Ordered by: standard name

ncalls tottime percall cumtime percall filename:lineno(function)
99999 27.569 0.000 27.569 0.000 <string>:1(<lambda>)
1 0.005 0.005 46.933 46.933 <string>:1(<module>)
1 0.000 0.000 0.000 0.000 {method 'disable' of '_lsprof.Profiler' objects}
1 19.341 19.341 46.911 46.911 {reduce}
1 0.017 0.017 0.017 0.017 {zip}



In [722]: cProfile.run('list(itertools.chain(*zip(a, b)))')
3 function calls in 0.022 seconds

Ordered by: standard name

ncalls tottime percall cumtime percall filename:lineno(function)
1 0.014 0.014 0.022 0.022 <string>:1(<module>)
1 0.000 0.000 0.000 0.000 {method 'disable' of '_lsprof.Profiler' objects}
1 0.008 0.008 0.008 0.008 {zip}

@chlx 你用的t, m非常小吧.

@gkiwi Underscore啊,http://underscorejs.org/

@xieranmaya 谢谢.看了下,功能很强大,万能的下划线'_' .